Generalised form of a four-digit number abdc is
(a) 1000 a + 100 b + 10 c + d
(b) 1000 a + 100 c + 10 b + d
(c) 1000 a + 100 b + 10 d + c
(d) a × b × c × d
Generalised form of a two-digit number xy is
(a) x + y
(b) 10x + y
(c) 10x – y
(d) 10y + x
The usual form of 1000a + 10b + c is
(a) abc
(b) abco
(c) aobc
(d) aboc
Let abc be a three-digit number. Then abc – cba is not divisible by
(a) 9
(b) 11
(c) 18
(d) 33
The sum of all the numbers formed by the digits x, y and z of the number xyz is divisible by
(a) 11
(b) 33
(c) 37
(d) 74
A four-digit number aabb is divisible by 55. Then possible value(s) of b is/are
(a) 0 and 2
(b) 2 and 5
(c) 0 and 5
(d) 7
Let abc be a three digit number. Then abc + bca + cab is not divisible by
(a) a + b + c
(b) 3
(d) 9
A four-digit number 4ab5 is divisible by 55. Then the value of b – a is
(a) 0
(b) 1
(c) 4
(d) 5
If A 3 + 8 B = 150, then the value of A + B is
(a) 13 (b) 12 (c) 17 (d) 15
If 5 A × A = 399, then the value of A is
(a) 3 (b) 6 (c) 7 (d) 9
If 6 A × B = A 8 B, then the value of A – B is
(a) –2 (b) 2 (c) –3 (d) 3
The difference of a two–digit number and the number obtained by reversing its digits is always divisible by ___________.
The difference of three-digit number and the number obtained by putting the digits in reverse order is always divisible by 9 and ___________.
If
then A = ___________ and B = ___________
Then A = _________ and B = _________
then B = ______________
If the digit 1 is placed after a 2-digit number whose tens is t and one’s digit is u, the new number is ______.
A two-digit number ab is always divisible by 2 if b is an even number.
A three-digit number abc is divisible by 5 if c is an even number.
A four-digit number abcd is divisible by 4 if ab is divisible by 4.
A three-digit number abc is divisible by 6 if c is an even number and a + b + c is a multiple of 3.
Number of the form 3N + 2 will leave remainder 2 when divided by 3.
Number 7N + 1 will leave remainder 1 when divided by 7.
If a number a is divisible by b, then it must be divisible by each factor of b.
If AB × 4 = 192, then A + B = 7.
If AB + 7C = 102, where B ≠ 0, C ≠ 0, then A + B + C = 14.
If 213x 27 is divisible by 9, then the value of x is 0.
If N ÷ 5 leaves remainder 3 and N ÷ 2 leaves remainder 0, then N ÷ 10 leaves remainder 4.
Find the least value that must be given to number a so that the number 91876a2 is divisible by 8.
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