Ncert exemplar solutions mathematics class 8 Solutions for Chapter 13 playing with numbers

Exercises in Chapter 13 playing with numbers Grade 8

Playing with Numbers - Exercise

Questions in Playing with Numbers - Exercise

Generalised form of a four-digit number abdc is

(a) 1000 a + 100 b + 10 c + d

(b) 1000 a + 100 c + 10 b + d

(c) 1000 a + 100 b + 10 d + c

(d) a × b × c × d

Generalised form of a two-digit number xy is

(a) x + y

(b) 10x + y

(c) 10x – y

(d) 10y + x

The usual form of 1000a + 10b + c is

(a) abc

(b) abco

(c) aobc

(d) aboc

Let abc be a three-digit number. Then abc – cba is not divisible by

(a) 9

(b) 11

(c) 18

(d) 33

The sum of all the numbers formed by the digits x, y and z of the number xyz is divisible by

(a) 11

(b) 33

(c) 37

(d) 74

A four-digit number aabb is divisible by 55. Then possible value(s) of b is/are

(a) 0 and 2

(b) 2 and 5

(c) 0 and 5

(d) 7

Let abc be a three digit number. Then abc + bca + cab is not divisible by

(a) a + b + c

(b) 3

(c) 37

(d) 9

A four-digit number 4ab5 is divisible by 55. Then the value of b – a is

(a) 0

(b) 1

(c) 4

(d) 5

If A 3 + 8 B = 150, then the value of A + B is

(a) 13 (b) 12 (c) 17 (d) 15

If 5 A × A = 399, then the value of A is

(a) 3 (b) 6 (c) 7 (d) 9

If 6 A × B = A 8 B, then the value of A – B is

(a) –2 (b) 2 (c) –3 (d) 3

The difference of a two–digit number and the number obtained by reversing its digits is always divisible by ___________.

The difference of three-digit number and the number obtained by putting the digits in reverse order is always divisible by 9 and ___________.

If

then A = ___________ and B = ___________

If

Then A = _________ and B = _________

If

then B = ______________

If the digit 1 is placed after a 2-digit number whose tens is t and one’s digit is u, the new number is ______.

A two-digit number ab is always divisible by 2 if b is an even number.

A three-digit number abc is divisible by 5 if c is an even number.

A four-digit number abcd is divisible by 4 if ab is divisible by 4.

A three-digit number abc is divisible by 6 if c is an even number and a + b + c is a multiple of 3.

Number of the form 3N + 2 will leave remainder 2 when divided by 3.

Number 7N + 1 will leave remainder 1 when divided by 7.

If a number a is divisible by b, then it must be divisible by each factor of b.

If AB × 4 = 192, then A + B = 7.

If AB + 7C = 102, where B ≠ 0, C ≠ 0, then A + B + C = 14.

If 213x 27 is divisible by 9, then the value of x is 0.

If N ÷ 5 leaves remainder 3 and N ÷ 2 leaves remainder 0, then N ÷ 10 leaves remainder 4.

Find the least value that must be given to number a so that the number 91876a2 is divisible by 8.

Was This helpful?

Chapters in this book

Rational Numbers

Squares and Square Roots & Cubes and Cube Roots

Linear Equations in One Variable

Understanding Quadrilaterals & Practical Geometry

Visualising Solid Shapes

Algebraic Expressions and Identities & Factorisation

Exponents and Powers

Comparing Quantities

Direct and Inverse Proportions

Introduction to Graphs

Playing with Numbers

lido-difference

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE

Grade 1

Grade 2

Grade 3

Grade 4

Grade 5

Grade 6

Grade 7

Grade 8

Grade 9

Grade 10

Maths
ICSE

Class 1

Class 2

Class 3

Class 4

Class 5

Class 6

Class 7

Class 8

Science
CBSE

Grade 5

Grade 6

Grade 7

Grade 8

Grade 9

Grade 10

Science
ICSE

Class 5

Class 6

Class 7

Class 8

Class 9

English
CBSE

Grade 1

Grade 2

Grade 3

Grade 4

Grade 5

Grade 6

Grade 7

Grade 8

Grade 9

Grade 10

English
ICSE

Class 4

Class 5

Class 6

Class 7

Coding

Grade 1

Grade 2

Grade 3

Grade 4

Grade 5

Grade 6

Grade 7

Grade 8

Grade 9

Quick Links

Terms & Policies

Terms & Policies

Selina Question Bank

Maths

Physics

Biology

Allied Question Bank

Chemistry

Connect with us on social media!

2022 © Quality Tutorials Pvt Ltd All rights reserved