Draw a line AB and take a point P outside it. Draw a line CD parallel to AB and passing through the point P.
Construct a ΔABC in which BC = 3.6 cm, AB = 5 cm and AC = 5.4 cm. Draw the perpendicular bisector of the side BC.
Construct a ΔABC in which AB = AC = 4.8cm and BC = 5.3cm. Measure ∠B and ∠C. Draw AD ⊥ BC.
Construct a ΔABC in which AB = 3.8 cm, ∠A = 60^{\circ} and AC = 5 cm.
Mark against the correct answer in the following:
The supplement of 45^{\circ} is
\begin{array}{llll} \text { (a) } 45^{\circ} & \text { (b) } 75^{\circ} & \text { (c) } 135^{\circ} & \text { (d) } 155^{\circ} \end{array}
An angle is its own complement. The measure of the angle is
(a) 30^{\circ} (b) 45^{\circ} (c) 90^{\circ} (d) 60^{\circ}
An angle is one-fifth of its supplement. The measure of the angle is
(a) 30^{\circ} (b) 15^{\circ} (c) 75^{\circ} (d) 150^{\circ}
An angle is 32^{\circ} less than its supplement. The measure of the angle is
(a) 37^{\circ} (b) 74^{\circ} (c) 148^{\circ} (d) none of these
In the given figure, AOB is a straight line and the ray OC stands on it. If ∠BOC = 132^{\circ}, then ∠AOC =?
(a) 68^{\circ} (b) 48^{\circ} (c) 42^{\circ} (d) none of these
In the given figure, AOB is a straight line, \angle \mathrm{AOC}=68^{\circ} \text { and } \angle \mathrm{BOC}=\mathrm{x}^{\circ}.
(a) 32 (b) 22 (c) 112 (d) 132
In the given figure, it is given that AOB is a straight line and 4x = 5y. What is the value of x?
(a) 100 (b) 105 (c) 110 (d) 115
In the given figure, two straight lines AB and CD intersect at a point O and ∠AOC = 50^{\circ}. Then ∠BOD =?
(a) 40^{\circ} (b) 50^{\circ} (c) 130^{\circ} (d) 60^{\circ}
In the given figure, AOB is a straight line, \angle \mathrm{AOC}=(3 \mathrm{x}-8)^{\circ}, \angle \mathrm{AOC}=50^{\circ} \text { and } \angle \mathrm{BOD}=(\mathrm{x}+10)^{\circ}. The value of x is
(a) 32 (b) 42 (c) 36 (d) 52
In ΔABC, side BC has been produced to D. if \angle \mathrm{BAC}=45^{\circ} \text { and } \angle \mathrm{ABC}=55^{\circ}, \text { then } \angle \mathrm{ACD}=?
(a) 80^{\circ} (b) 90^{\circ} (c) 100^{\circ} (d) 110^{\circ}
In the given figure, side BC of ΔABC is produced to D such that \angle \mathrm{ABC}=70^{\circ} \text { and } \angle \mathrm{ACD}=120^{\circ}. Then, ∠BAC =?
(a) 60^{\circ} (b) 50^{\circ} (c) 70^{\circ} (d) 35^{\circ}