NCERT Exemplar Solutions - Mathematics - class 7 solutions for Chapter 4 Simple Equations

The solution of the equation ax + b = 0 is

(a) a/b (b) –b (c) –b/a (d) b/a

If a and b are positive integers, then the solution of the equation ax = b will always be a

(a) positive number (b) negative number (c) 1 (d) 0

Which of the following is not allowed in a given equation?

(a) Adding the same number to both sides of the equation.

(b) Subtracting the same number from both sides of the equation.

(c) Multiplying both sides of the equation by the same non-zero number.

(d) Dividing both sides of the equation by the same number.

The solution of which of the following equations is neither a fraction nor an integer? (a) 2x + 6 = 0 (b) 3x – 5 = 0

(c) 5x – 8 = x + 4 (d) 4x + 7 = x + 2

The equation which cannot be solved in integers is

(a) 5y – 3 = – 18 (b) 3x – 9 = 0

(c) 3z + 8 = 3 + z (d) 9y + 8 = 4y – 7

If 7x + 4 = 25, then x is equal to

(a) 29/7 (b) 100/7 (c) 2 (d) 3

The solution of the equation 3x + 7 = – 20 is

(a) 17/7 (b) -9 (c) 9 (d) 13/3

The value of y for which the expressions (y – 15) and (2y + 1) become equal is

(a) 0 (b) 16 (c) 8 (d) – 16

If k + 7 = 16, then the value of 8k – 72 is

(a) 0 (b) 1 (c) 112 (d) 56

If 43m = 0.086, then the value of m is

(a) 0.002 (b) 0.02 (c) 0.2 (d) 2

x exceeds 3 by 7, can be represented as

(a) x + 3 = 2 (b) x + 7 = 3 (c) x – 3 = 7 (d) x – 7 = 3

The equation having 5 as a solution is:

(a) 4x + 1 = 2 (b) 3 – x = 8 (c) x – 5 = 3 (d) 3 + x = 8

The equation having – 3 as a solution is:

(a) x + 3 =1 (b) 8 + 2x = 3 (c) 10 + 3x = 1 (d) 2x + 1 = 3

Which of the following equations can be formed starting with x = 0?

(a) 2x + 1 = – 1 (b) x/ 2 + 5 = 7

(c) 3x – 1 = – 1 (d) 3x – 1 = 1

Which of the following equations cannot be formed using the equation x = 7?

(a) 2x + 1 = 15 (b) 7x – 1 = 50

(c) x – 3 = 4 (d) (x/7) – 1 = 0

If (x/2) = 3, then the value of 3x + 2 is

(a) 20 (b) 11 (c) 13/2 (d) 8

Which of the following numbers satisfy the equation –6 + x = –12?

(a) 2 (b) 6 (c) – 6 (d) – 2

Shifting one term from one side of an equation to another side with a change of sign is known as

(a) commutativity (b) transposition

(c) distributivity (d) associativity

The sum of the two numbers is 60 and their difference is 30.

(a) If the smaller number is x, the other number is ___________.(use sum)

(b) The difference in numbers in terms of x is _____________.

(c) The equation formed is _____________.

(d) The solution to the equation is _________.

(e) The numbers are _____________and __________.

The sum of the two numbers is 60 and their difference is 30.

(a) If the smaller number is x, the other number is ___________.(use sum)

(b) The difference in numbers in terms of x is _____________.

(c) The equation formed is _____________.

(d) The solution to the equation is _________.

(e) The numbers are _____________and __________.

The sum of the two numbers is 81. One is twice the other.

(a) If the smaller number is x, the other number is __________.

(b) The equation formed is __________.

(c) The solution to the equation is ________________.

(d) The numbers are ______________and ___________.

In a test, Abha gets twice the marks as that of Palak. Two times

Abha's marks and three times Palak's marks make 280.

(a) If Palak gets x marks, Abha gets marks___.

(b) The equation formed is _________________.

(c) The solution of the equation is _________.

(d) Marks obtained by Abha are ____________ .

The length of a rectangle is two times its breadth. Its perimeter is

60 cm.

(a) If the breadth of rectangle is x cm, the length of the rectangle is _________

(b) Perimeter in terms of x is ___________.

(c) The equation formed is _____________.

(d) The solution to the equation is _______.

In a bag there are 5 and 2 rupee coins. If they are equal in number

and their worth is ₹ 70, then

(a) The worth of x coins of ₹ 5 each __________.

(b) The worth of x coins of ₹ 2 each _____________.

(c) The equation formed is ____________.

(d) There are _________ 5 rupee coins and _______________ 2 rupee coins.

In a Mathematics quiz, 30 prizes consisting of 1st and 2nd prizes only are to be given. 1st and 2nd prizes are worth ₹ 2000 and ₹ 1000 respectively. If the total prize money is ₹ 52,000 then show that:

(a) If 1st prizes are x in number the number of 2nd prizes are .

(b) The total value of prizes in terms of x are ____________.

(c) The equation formed is _______________________.

(d) The solution of the equation is _______________.

(e) The number of 1st prizes are ___________ and the number of 2nd prizes are _____________.

If z + 3 = 5, then z = ___________.

_________ is the solution of 3x + 10 = 7.

_______________ is the solution of the equation 3x – 2 =7.

If 2x + 3 = 5, then value of 3x + 2 is _________.

In integers, 4x – 1 = 8 has _________ solution.

In natural numbers, 4x + 5 = – 7 has __________ solution.

In natural numbers, x – 5 = – 5 has __________ solution.

In whole numbers, x + 8 = 12 – 4 has ____________ solution.

If 5 is added to three times a number, it becomes the same as 7 is subtracted from four times the same number. This fact can be represented as ___________.

x + 7 = 10 has the solution ______.

x – 0 = ___________; when 3x = 12.

x – 1= _________; when 2x = 2.

x – __________= 15; when x/2 = 6.

The solution of the equation x + 15 = 19 is _____________.

Finding the value of a variable in a linear equation that the equation is called a ___________ of the equation.

Any term of an equation may be transposed from one side of the equation to the other side of the equation by changing the ___________ of the term.

If (9/5)x = (18/5), then x = ______________

If 3 – x = -4, then x = __________

If x – ½ = – ½, then x = __________.

If (1/6) – x = 1/6, then x = ___________.

If 10 less than a number is 65, then the number is ____________.

If a number is increased by 20, it becomes 45. Then the number is _________.

If 84 exceeds another number by 12, then the other number is _________.

If x – (7/8) = 7/8, then x = ____________

5 is the solution of the equation 3x + 2 = 17.

9/5 is the solution of the equation 4x – 1 = 8.

4x – 5 = 7 does not have an integer as its solution.

One-third of a number added to itself gives 10, can be represented as (x/3) + 10 = x

3/2 is the solution of the equation 8x – 5 = 7.

If 4x – 7 = 11, then x = 4.

If 9 is the solution of variable x in the equation ((5x – 7)/2) = y, then the value of y is 28.

Ncert exemplar solutions mathematics class 7 Solutions for Chapter 4 simple equations