A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be roughly.
Answer is (a) 1020
Explanation:
I = Q/t
Q= It
Q= 1 x 16
Q= 16 q
Q=ne
n = Q/e
n = 16 /1.6 x 10-19
n = 10 x 1019
n = 1020 electrons
The number of electrons flowing is 1020 electrons
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