10 ml of a solution of NaOH is found to be completely neutralised by 8ml of a given solution of HCl. If we take 20 ml of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralise it will be :
(a) 4 ml
(b) 8ml
(c)12 ml
(d) 16ml
Option (d) is the answer.
It is given that 10ml of a solution of NaOH is completely neutralized by 8ml of a solution of HCl. When 20ml of the solution of NaOH is taken, it is double the amount taken before and will require double the solution of HCl taken earlier. Thus, 16ml is to be added to completely neutralize 20 ml of NaOH.
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