chapter-header

NCERT Exemplar Solutions Class 9 Science Solutions for Motion - Exercise in Chapter 8 - Motion

Question 30 Motion - Exercise

A car starts from rest and moves along the x-axis with a constant acceleration of 5 m/s2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?

Answer:

Car Starts from rest hence Initial velocity u=o acceleration a=5 m/s2 and time t=8s

v = u+at

v = 0+5×8

v = 40ms-1

From second equation

s = ut +12at2

s = 0x8 + 12x5x(8)2

s = 12x5x(8)2

s = 12x5x64

s = 5×32=160 is the distance coveed in 8 seconds.

The total distance covered in 12 seconds, therefore, is 160+160=320m

Connect with us on social media!
2022 © Quality Tutorials Pvt Ltd All rights reserved