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**A car starts from rest and moves along the x-axis with a constant acceleration of 5 m/s2** **for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?**

Answer:

Car Starts from rest hence Initial velocity u=o acceleration a=5 m/s2 and time t=8s

v = u+at

v = 0+5×8

v = 40ms-1

From second equation

s = ut +12at2

s = 0x8 + 12x5x(8)2

s = 12x5x(8)2

s = 12x5x64

s = 5×32=160 is the distance coveed in 8 seconds.

The total distance covered in 12 seconds, therefore, is 160+160=320m

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