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NCERT Solutions Class 9 Science Solutions for Work and Energy - Exercise 11.5 in Chapter 11 - Work and Energy

Question 13 Work and Energy - Exercise 11.5

An object of mass, m is moving with a constant velocity, v. How much work should be done on the object in order to bring the object to rest?

Answer:

\text { The formula for kinetic energy }=\frac{1}{2} m v^{2}

\text { The kinetic energy of the object at rest = 0 }

\text { Change in kinetic energy = Work done on an object }

=\frac{1}{2} m v^{2}-0

=\frac{1}{2} m v^{2}

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