Ncert solutions

Ncert solutions

Ncert solutions

Grade 8

CHAPTERS

1. Crop Production and Management

2. Microorganisms: Friend and Foe

3. Synthetic Fibres and Plastic

4. Materials: Metals and Non-Metals

7. Conservation of Plants and Animals

8. Cell — Structure and Functions

10. Reaching the Age of Adolescence

14. Chemical Effects and Electric Current

Q 15) The radius of Jupiter is 11 times the radius of the Earth. Calculate the ratio of the volumes of Jupiter and the Earth. How many Earths can Jupiter accomodate?

Solution 15:

The volume of sphere = 4/3 ℼr3

Let the radius of the earth be ‘r’

The radius of Jupiter = 11 ✕ r

The volume of earth = 4/3 ℼr3

The volume of Jupiter = 4/3 ℼ (11r)3

= 4/3 ✕ (22 / 7) ✕ (11 ✕ r)3

Required\ ratio=\frac{Volume\ of\ the\ Jupiter}{Volume\ of\ the\ Earth}=\frac{\frac{4}{3}\times\left(\frac{22}{7}\right)\times1331\times r^3}{\frac{4}{3}\times\left(\frac{22}{7}\right)\times r^3}=1331

i.e. 1331 : 1

The volume of Jupiter is 1331 times the volume of the earth. Thus, around 1331 earths can fit into one jupiter.

Still have questions? Our expert teachers can help you out

Book a free class nowSolution 15:

The volume of sphere = 4/3 ℼr3

Let the radius of the earth be ‘r’

The radius of Jupiter = 11 ✕ r

The volume of earth = 4/3 ℼr3

The volume of Jupiter = 4/3 ℼ (11r)3

= 4/3 ✕ (22 / 7) ✕ (11 ✕ r)3

Required\ ratio=\frac{Volume\ of\ the\ Jupiter}{Volume\ of\ the\ Earth}=\frac{\frac{4}{3}\times\left(\frac{22}{7}\right)\times1331\times r^3}{\frac{4}{3}\times\left(\frac{22}{7}\right)\times r^3}=1331

i.e. 1331 : 1

The volume of Jupiter is 1331 times the volume of the earth. Thus, around 1331 earths can fit into one jupiter.

Still have questions? Our expert teachers can help you out

Book a free class nowLido

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