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NCERT Exemplar Solutions Class 10 Science Solutions for Electricity - Exercise in Chapter 12 - Electricity

Question 14 Electricity - Exercise

A current of 400 mA is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 1/4th of a minute would be roughly

Answer:

Answer is (a) 1020

Explanation:

I = Q/t

Q= It

Q= 1 x 16

Q= 16 q

Q=ne

n = Q/e

n = 16 /1.6 x 10-19

n = 10 x 1019

n = 1020 electrons

The number of electrons flowing is 1020 electrons

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