# Selina Solutions Class 9 Physics Solutions for Exercise 7C in Chapter 7 - Chapter 7 Reflection Of Light

Question 48 Exercise 7C

A concave mirror forms a real image of an object placed in front of it at a distance 30cm, of size three times the size of the object. Find (a) the focal length of the mirror (b)

Given:

(a)Distance of the object (u) = 30cm (negative)

We know that,

\mathrm{m}=\frac{1}{0}=\frac{30}{0}=3

For a real object, the value of â€˜mâ€™ is negative

m = -3

Asm=-\frac{v}{u}

=> v = 3u

=> v = 3 x 30 = 90 cm

Therefore, the image is formed 90cm in front of the mirror.

Mirror formula can be given by

Therefore, the image is formed 90cm in front of the mirror.

The mirror formula can be given by

\begin{array}{c} \frac{1}{u}+\frac{1}{v}=\frac{1}{f} \\ \frac{1}{f}=\frac{1}{30}+\frac{1}{90}=-\frac{4}{90} \\ f=-22.5 \mathrm{cm} \end{array}

The focal length of the mirror is 22.5cm

Related Questions
Exercises

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!