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A rubber ball floats on water with its 1/3rd volume outside water. What is the density of rubber

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To find the density of rubber

Consider the volume of the ball to be V

As per the given data, the volume of the ball above the water surface = (1/3)V

 The volume of the ball immersed in water= V – 1/3V = 2/3V

We know from the principle of floatation

\text { Nolume of rubber ball immersed }=\frac{\text { density of rubber }}{\text { Net volume of the ball }}

\begin{array}{l} \Rightarrow \frac{2}{3}=\frac{\text { density of rubber }}{1000} \\ \Rightarrow \text { Density of rubber }=1000 \times \frac{2}{3}=667 \mathrm{kg} \mathrm{m}^{3} \end{array}

"hello everyone welcome to leader learning i'm gurpreet your science tutor today's question is a rubber ball floats on water with its one-third volume outside the water what will be the density of rubber so here a situation is given that a rubber ball that is floating on the water is one third the volume outside of water so what will be the density of water here let us start our answer here we will consider the volume of ball of ball which is equals to v we will consider the volume of ball as v volume so according to the question the volume of ball above the water above the water is equals to one third the volume of ball so the volume of ball immersed ball emerged in water is equals to the total volume minus the volume of ball above the water that is one third of volume so you will get the volume of polymers is 2 by 3 of volume okay now here we have to calculate the density density can be calculated as two by three into the volume volume will be one thousand here and you will get it as six six seven kilogram meter cube this is the density of the rubber for more such videos please subscribe leader learning and for any doubts drop a comment thank you"

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