A body of volume 100cm3 weighs 1 kgf in air. Find: (i) its weight in water and (ii) its relative density.
Given:
Volume of the body = 100cm3
Weight of the body in the air, W1= 1kgf or 1000gf
Let Weight of the body in water be W2
We know that R.D of water is 1 and that of a solid is 10
(i) To find the weight of the body in water
\text { Relative density of the body }=\frac{w_{1}}{W_{1}-W_{2}} x \text { relative density of water }
\begin{array}{l} 10=\frac{1000}{1000-W_{2}} \times 1 \\ 10\left(1000-W_{2}\right)=1000 \end{array}
W2 = 1000 – 100 = 900 gf
(ii) To find the relative density of the body
Density of the body = mass/volume
= 1000/100 = 10gf
Relative density is equivalent to density in C.G.S. with no unit, hence R.D. of the body is 10.
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