A body weighs W1 gf in air and when immersed in a liquid it weighs W2 gf, while it weighs W3 gf on immersing it in water. Find: (i) volume of the body (ii) upthrust due to liquid (iii)
relative density of the solid and (iv)relative density of the liquid
Given:
W1 = weight of the body in air
W2 = weight of the body when immersed in liquid
W3 = weight of the body when immersed in water
(i) Volume of the body = W1-W3 cm3
(ii) Upthrust due to liquid = W1-W2 gf
\text { (iii) } \quad \text { relative density of the solid }=\frac{\text { weight of the solid in air }}{\text { weight in air-weight in water }}=\frac{W_{1}}{W_{1}-W_{3}}
\text { (iv) relative density of the liquid }=\frac{w_{1}-w_{2}}{w_{1}-w_{3}}
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