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**A body weighs W1 gf in air and when immersed in a liquid it weighs W2 gf, while it weighs W3 gf on immersing it in water. Find: (i) volume of the body (ii) upthrust due to liquid (iii)**

**relative density of the solid and (iv)relative density of the liquid**

Answer:

Given:

W1 = weight of the body in air

W2 = weight of the body when immersed in liquid

W3 = weight of the body when immersed in water

(i) Volume of the body = W1-W3 cm3

(ii) Upthrust due to liquid = W1-W2 gf

\text { (iii) } \quad \text { relative density of the solid }=\frac{\text { weight of the solid in air }}{\text { weight in air-weight in water }}=\frac{W_{1}}{W_{1}-W_{3}}

\text { (iv) relative density of the liquid }=\frac{w_{1}-w_{2}}{w_{1}-w_{3}}

"hello everyone welcome to lido this is
priya
and here we have a question to solve let
us look into the question
now a body weighs w1
gf in 8 and when it is immersed in a
liquid
it weighs w2gf while it weighs
w3gf on immersing it in
water find volume of the body
afters due to liquid and three
relative density of the solid and four
relative density of the liquid so
let us give the
first one volume of the body
volume of the body can be given
as
can be given as
w 1 minus w3
centimeter cube so what is w1
it's a weight of the object in air
and w3 is the weight immersed in the
water so these two when we subtract
these two will get the volume of
object and the second one
we need to find out address due to
liquid
for this
a thrust
due to
liquid
equal to w1 minus
w to gf
so what is w1 weight of the object in
air and w2 is the weight of the object
in
liquid so the uprest will be w1 minus
w2 and let us see the third one we need
to find out
relative density of
solid for that relative
density of
solid equal to
weight
of solid
in air
by
weight of solid
in air minus
weight of solid in water
weight of solid in a minus weight of
solid in
water so what is the weight of a solid
in
air it is w1
and weight of solid in air is again w1
minus w3
will gives the relative density of
solid and the fourth one to find out the
relative density of liquid
relative density of
liquid
equal to w1 minus
w2 by
w 1 minus w
3 so if we subtract w 1 minus w
2 by w 1 minus w 3
will get the relative density of liquid
hope you understand this video
if you like my video please subscribe to
a little channel and if you have any
doubts you can keep a message in comment
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thank you"

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