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Selina Solutions Class 9 Physics Solutions for Exercise 5A in Chapter 5 - Chapter 5 Upthrust In Fluids Archimedes Principle And Floatation
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Question 39 Exercise 5A
A block of mass 3.5kg displaces 1000cm3 of water when fully immersed inside it. Calculate:
(i) the volume of the body, (ii) the upthrust on the body, and (iii) the apparent weight of the body in water.
Answer:
Given:
Mass of block = 3.5kg => weight of the body = 3.5kgf
The volume of the water displaced when completely immersed in water = 1000cm3
(i) To find the volume of the body when completely immersed in a liquid is equivalent to the volume of the water displaced
Volume of the block = 1000 cm3 or 0.001m3
(ii) Upthrust acting on the body = volume of the body x density of water x g
= 0.001 x 1000 x g = 1 kgf
(iii) The apparent weight of body in water= true weight – upthrust
=3.5-1 = 2.5kgf
Video transcript
"hello everyone welcome to leader this is
priya
and here we have a question about to
solve
let us look into the question
a block of mass 3.5 kgs
displaces 1000 centimeter cube of water
when fully immersed inside it
calculate the volume of the body
second the uptress on the body
and third the apparent weight of the
body
in what so to find out the first one
the volume of the of the body
before that i'm just giving you the
values what has given
in the question it has given
the mass of
block
which is 3.5
kgs
that means we can also
write the we can find the weight
of this block
by adding the force of gravity
acting on it so weight of block will be
3.5 k
g f the volume of the water displaced
when completely immersed in
in water is 1000 centimeter cube
so the volume of water
the volume of water displaced when
completely immersed equal to
1000 centimeter
cube and now to find out the volume
of the body when completely immersed in
the liquid
will be equal to the volume of water
displaced
so then volume of the block what will be
the volume of the block
volume
of the block
volume of the block will be obviously
1000 centimeter
cube or in meters we can express this as
0.000
one meter cube so this is the volume of
block because
the volume of block will be equal to the
volume of water which is
displaced when the block is fully
immersed inside it
so we have found out the first one now
we'll see the
second one which we have to find out the
uprest on the body
as we know aktrast
acting on the body
is equal to will be always equal to
volume
of the body
into density of water
and density of water and gravity
we know the volume of the liquid which
is zero point 0.001
meter cube and we know the density of
water which is
1000 and we know the g
we take it as a g which implies
1 k g
f so up just acting on the body will be
one kgf
now we see the last one we have to find
out the apparent
weight of the body inverter to find out
this
that will be a true weight
true weight of the body
minus upthrust
so what's the true weight it is 35
and what 3.5 so what is the upthrust
it is nearly 1 so when we subtract this
we'll get 2.5 k
g f so this is the apparent weight of
the
body hope you understand this video if
you like my video please subscribe
to another channel and if you have any
doubts you can keep a message in comment
box thank you"
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