# Selina Solutions Class 9 Physics Solutions for Exercise 5A in Chapter 5 - Chapter 5 Upthrust In Fluids Archimedes Principle And Floatation

Question 38 Exercise 5A

A block of wood is floating on water with its dimensions 50cm x 50 cm x 50 cm inside water.

Calculate the buoyant force acting on the block. Take g = 9.8N kg-1.

Volume of the block = 50cm x 50cm x 50cm = 125000cm3

Expressing volume in m3 => 0.125 m3

g = 9.8N kg-1 or 9.8m/s2

We know that buoyant force = V ρ g

 0.125 x 1000 x 9.8 = 1225N

Video transcript
"hello everyone welcome to little this is priya and here we have a question to calculate the biopic which is to calculate the biome force acting on the block let us look into the question a block of wood is floating on water with its dimensions 50 into 50 into 50 centimeter inside water calculate the biond force acting on the block take g equal to 9.8 newton per kg so what we know from this question is we know the volume which is 50 into 50 into 50 centimeters so when we multiply this we'll get one lag 25 000 centimeter here so the volume of the cube is 1 lakh 25 000 centimeter cube and expressing volume in meters when we express this volume in meters then equal to zero point one two five meter cube so this is the volume in meter cube and we know g equal to 9.8 newton per kg or we can also write this as 9.8 meters per second square this is a gravity and we know the biome force equal to bio force equal to v rho g as we know volume is 0.125 and we know the density of liquid which is 1 000 and we know the gravity which is one nine point eight so when we multiply these three we get the value of one thousand two hundred and twenty five newton this is the biome force exhibiting by that block of code hope you understand this video if you like my video please subscribe to our little channel and if you have any doubts you can keep a message in comment box thank you"
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