# Selina Solutions Class 9 Physics Solutions for Exercise 4A in Chapter 4 - Chapter 4 Pressure In Fluids And Atmospheric Pressure

Question 48 Exercise 4A

A force of 50kgf is applied to the smaller piston of a hydraulic machine. Neglecting friction, find the force exerted on the large piston, if the diameters of the pistons are 5cm and 25cm respectively.

Comparing the diameter of the narrow piston and broader piston = 5/25 or 5:25 = 25:625

Force exerted on narrow piston, F1 = 50kgf

Consider F2 to be the force exerted on the broader piston

We know from the principle of Hydraulic machine,

Pressure on narrow piston = pressure on the broader piston

\begin{array}{l} \frac{\mathrm{F}_{1}}{\mathrm{A}_{1}}=\frac{\mathrm{F}_{2}}{\mathrm{A}_{2}} \\ \frac{\mathrm{F}_{1}}{\mathrm{F}_{2}}=\frac{\mathrm{A}_{1}}{\mathrm{A}_{2}} \\ \Rightarrow 50 / \mathrm{F}_{2}=25 / 625 \\ \mathrm{F}_{2}=1250 \mathrm{kgf} \end{array}

Related Questions
Exercises

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!