- Chapter 1 – Measurements and Experimentation
- Chapter 2 Motion In One Dimension
- Chapter 3 Laws Of Motion
- Chapter 4 Pressure In Fluids And Atmospheric Pressure
- Chapter 5 Upthrust In Fluids Archimedes Principle And Floatation
- Chapter 6 Heat And Energy
- Chapter 7 Reflection Of Light
- Chapter 8 Propogation Of Sound Waves
- Chapter 9 Current Electricity
- Chapter 10 Magnetism
Selina Solutions Class 9 Physics Solutions for Exercise 4A in Chapter 4 - Chapter 4 Pressure In Fluids And Atmospheric Pressure
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A force of 50kgf is applied to the smaller piston of a hydraulic machine. Neglecting friction, find the force exerted on the large piston, if the diameters of the pistons are 5cm and 25cm respectively.
Comparing the diameter of the narrow piston and broader piston = 5/25 or 5:25 = 25:625
Force exerted on narrow piston, F1 = 50kgf
Consider F2 to be the force exerted on the broader piston
We know from the principle of Hydraulic machine,
Pressure on narrow piston = pressure on the broader piston
\begin{array}{l} \frac{\mathrm{F}_{1}}{\mathrm{A}_{1}}=\frac{\mathrm{F}_{2}}{\mathrm{A}_{2}} \\ \frac{\mathrm{F}_{1}}{\mathrm{F}_{2}}=\frac{\mathrm{A}_{1}}{\mathrm{A}_{2}} \\ \Rightarrow 50 / \mathrm{F}_{2}=25 / 625 \\ \mathrm{F}_{2}=1250 \mathrm{kgf} \end{array}
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