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Selina Solutions Class 9 Physics Solutions for Exercise 4A in Chapter 4 - Chapter 4 Pressure In Fluids And Atmospheric Pressure
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A hammer exerts a force of 1.5N on each of the two nails A and B. The area of cross-section of the tip of the nail, A is 2mm^2 while that of nail B is 6 mm2 . Calculate pressure on each nail in pascal.
Answer:
Given:
Force acting on nail A is 1.5N, area = 2mm2
Expressing 2mm^2 in metre
1mm=0.001m
\therefore 1 \mathrm{mm}^{2}=1 \mathrm{mm} \times 1 \mathrm{mm}=0.001 \mathrm{m} \times 0.001 \mathrm{m}=1 \times 10^{-6} \mathrm{m}^{2}
Pressure on B = Force/area
\begin{array}{l} =1.5 /\left(2 \times 1 \times 10^{-6}\right) \\ =7.5 \times 10^{5} \mathrm{Pa} \end{array}
Pressure on B
\begin{array}{l} =1.5 /\left(6 \times 1 \times 10^{-6}\right) \\ =2.5 \times 10^{5} \mathrm{Pa} \end{array}
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