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Chapter 3 Laws Of Motion | Exercise 3E

Question 43

A body falls from the top of a building and reaches the ground 2.5s later. How high is the building? (Take g=9.8m/s^2)

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Given: g=9.8m/s^2, t=2.5s

Assume ‘h’ to be the height of the building

We know from the equation of motion,

\begin{array}{l} \mathrm{H}=\mathrm{ut}+1 / 2 \mathrm{gt}^{2} \\ \Rightarrow \mathrm{H}=1 / 2 \mathrm{gt}^{2} \\ \Rightarrow \mathrm{H}=1 / 2(9.8)(2.5)^{2} \\ \Rightarrow 30.6 \mathrm{m} \end{array}

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Question 43

A body falls from the top of a building and reaches the ground 2.5s later. How high is the building? (Take g=9.8m/s^2)

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Given: g=9.8m/s^2, t=2.5s

Assume ‘h’ to be the height of the building

We know from the equation of motion,

\begin{array}{l} \mathrm{H}=\mathrm{ut}+1 / 2 \mathrm{gt}^{2} \\ \Rightarrow \mathrm{H}=1 / 2 \mathrm{gt}^{2} \\ \Rightarrow \mathrm{H}=1 / 2(9.8)(2.5)^{2} \\ \Rightarrow 30.6 \mathrm{m} \end{array}

Our top 5% students will be awarded a special scholarship to Lido.

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