A body is dropped from the top of a tower. It acquires a velocity 20m/s on reaching the ground. Calculate the height of the tower. (Take g=10m/s^2)
Solution:
Given: u=0m/s, v=20 m/s, g=10m/s^2 ;
Assume ‘h’ to be the height of the tower
We know from the equation of motion;
\begin{array}{l} v^{2}-u^{2}=2 g s \\ (20)^{2}-0=2(10)(h) \\ h=400 / 20 \Rightarrow 20 m \end{array}
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