Selina Solutions Class 9 Physics Solutions for Exercise 3E in Chapter 3 - Chapter 3 Laws Of Motion

Question 26 Exercise 3E

A body is projected vertically upward with an initial velocity u. If acceleration due to gravity is g, the time for which it remains in the air, is:

(a) u/g

(b) ug

(d) u/2g

Answer:

Time taken ‘t’= u/g, time taken to travel upwards and remain in air is 2t= 2u/g

Video transcript

hello everyone welcome to lido learning i am gurpreet your science tutor today's question is a body is projected vertically upwards in a with an initial velocity u if acceleration due to gravity is g the time for which it remains in the air is a u by g b u g c 2u by g and d u by 2g so from the four options you have to select the time for which it remains in the air so time taken is calculated by initial velocity upon acceleration due to gravity that is g now time taken to travel upwards and remain in air in air is 2t is equals to 2u by g so your correct option will be option c that is 2u by g for more such videos please subscribe leader learning and for any doubts drop a comment thank you

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Exercises

Exercise 3A

Exercise 3B

Exercise 3C

Exercise 3D