Selina solutions
Our top 5% students will be awarded a special scholarship to Lido.

Chapter 3 Laws Of Motion | Exercise 3C

Question 31

A car of mass 480kg moving at a speed of 54km/h is stopped by applying brakes in 10s. Calculate the force applied by the brakes.

Looking to do well in your science exam ?  
Learn from an expert tutor. Book a free class!

Given: m=480kg, initial velocity, u=54km/h or 15m/s, final velocity, v=0m/s, t=10s, F=?

We know that acceleration is the rate of change of velocity

∴ acceleration = (v-u)/t

= (0-15)/10

= -1.5m/s2

The negative sign shows that it is retardation.

Force = m x a

= 480 (-1.5)

= 780N

Set your child up for success with Lido, book a class today!

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta

Question 31

A car of mass 480kg moving at a speed of 54km/h is stopped by applying brakes in 10s. Calculate the force applied by the brakes.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Given: m=480kg, initial velocity, u=54km/h or 15m/s, final velocity, v=0m/s, t=10s, F=?

We know that acceleration is the rate of change of velocity

∴ acceleration = (v-u)/t

= (0-15)/10

= -1.5m/s2

The negative sign shows that it is retardation.

Force = m x a

= 480 (-1.5)

= 780N

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
Connect with us on social media!
2021 © Quality Tutorials Pvt Ltd All rights reserved
`