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Selina solutions
Grade 9 
Physics
Selina Solutions CONCISE subject class 9-ICSE-Physics
Chapter 3 Laws Of Motion
Exercise 3C
Question 31
Physics
Selina Solutions CONCISE subject class 9-ICSE-Physics
Chapter 3 Laws Of Motion
Exercise 3C
Question 31
Chapter 3 Laws Of Motion | Exercise 3C
Question 31
CHAPTERS
1. Chapter 1 – Measurements and Experimentation
2. Chapter 2 Motion In One Dimension
4. Chapter 4 Pressure In Fluids And Atmospheric Pressure
5. Chapter 5 Upthrust In Fluids Archimedes Principle And Floatation
7. Chapter 7 Reflection Of Light
8. Chapter 8 Propogation Of Sound Waves
A car of mass 480kg moving at a speed of 54km/h is stopped by applying brakes in 10s. Calculate the force applied by the brakes.
Given: m=480kg, initial velocity, u=54km/h or 15m/s, final velocity, v=0m/s, t=10s, F=?
We know that acceleration is the rate of change of velocity
∴ acceleration = (v-u)/t
= (0-15)/10
= -1.5m/s2
The negative sign shows that it is retardation.
Force = m x a
= 480 (-1.5)
= 780N
Question 31
A car of mass 480kg moving at a speed of 54km/h is stopped by applying brakes in 10s. Calculate the force applied by the brakes.
Given: m=480kg, initial velocity, u=54km/h or 15m/s, final velocity, v=0m/s, t=10s, F=?
We know that acceleration is the rate of change of velocity
∴ acceleration = (v-u)/t
= (0-15)/10
= -1.5m/s2
The negative sign shows that it is retardation.
Force = m x a
= 480 (-1.5)
= 780N
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