Selina Solutions Class 9 Physics Solutions for Exercise 3C in Chapter 3 - Chapter 3 Laws Of Motion

Question 30 Exercise 3C

A force acts for 0.1s on a body of mass 2kg initially at rest. The force is then withdrawn and the body moves with a velocity of 2m/s. Find the magnitude of force.


Given: u=0, t=0.1s, m=2kg, final velocity v = 2m/s; F=?

We know that acceleration is the rate of change of velocity

Acceleration = (v-u)/t

= (2-0)/0.1

= 20m/s2

Force = ma

= 2 x 20 = 40N

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