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Selina Solutions Class 9 Physics Solutions for Exercise 3C in Chapter 3 - Chapter 3 Laws Of Motion
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A force of 10N acts on a body of mass 2kg for 3s, initially at rest. Calculate: (i) the velocity acquired by the body, and (ii) change in momentum of the body.
Answer:
Given: F=10N, m=2kg, t=3s; initial velocity u=0m/s
(i) To find final velocity v;
F=ma
a=F/m = 10/2=5m/s2
We know the 1st equation of motion;
v=u+at
=0+(5x3)
v=15m/s
(ii) To find change in momentum
Momentum change = final momentum – initial momentum
Δp=m(v-u)
=2(15-0) = 30 kg m/s
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