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Selina Solutions Class 9 Physics Solutions for Exercise 2C in Chapter 2 - Chapter 2 Motion In One Dimension

Question 10 Exercise 2C

A body initially moving with a velocity 20m/s strikes a target and comes to rest after penetrating a distance 10cm in the target. Calculate the retardation caused by the target.

Answer:

Given: u=20m/s, v=0, s=10cm or 0.1m We know that;

v^2= u^2 + 2as

(0)2=(20)2

2 (a)(0.1)

0 = 400 + 0.2a

-a = 400/0.2

a = -2000m/s^2

∴ Retardation is 2000m/s^2

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