 # Selina Solutions Class 9 Physics Solutions for Exercise 2B in Chapter 2 - Chapter 2 Motion In One Dimension

A ball moves on a smooth floor in a straight line with a uniform velocity 10m/s for 6s. At t=6s, the ball hits a wall and comes back along the same line to the starting point with the same speed. Draw the velocity-time graph and use it to find the total distance travelled by the ball and its displacement. To find the total distance, distance travelled in the first 6 seconds and the next 6 seconds must be calculated.

Distance covered in 6s = velocity x time

= 10 x 6 = 60 m/s

Distance covered in the next 6s = velocity x time

= 10 x 6 = 60 m/s

Total distance covered in a matter of 6+6= 12 seconds is

= 60 + 60 = 120m

As the ball returns to the initial point, the displacement is zero.

Related Questions
Exercises

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!