Chapter 2 Motion In One Dimension | Exercise 2A

Question

A car is moving in a straight line with speed 18km/h. It is stopped in 5s by applying the brakes. Find: (i) the speed of the car in m/s, (ii) the retardation and (iii) the speed of the car after 2s of applying the brakes.

Accepted Answer

Given: t=5s, intial velocity=18km/hr

(i) Expressing 18km/hr to m/s

$18 \mathrm{km} \mathrm{h}^{-1}=\frac{18 \times 1000 \mathrm{m}}{60 \times 60}=5 \mathrm{ms}^{-1}$

(ii) As the car comes to a halt, the final velocity is 0

Retardation is negative acceleration,

$\text { Retardation }=\frac{v-u}{t}=\frac{0-5}{5}=-1 \mathrm{m} / \mathrm{s}^{2}$

Retardation is $1m/s^2$

(iii) If ‘v’ is the speed of the car after 2s of applying brakes, then acceleration is

$\begin{array}{c} \text { Acceleration }=\frac{v-\mathrm{u}}{\mathrm{t}} \\ -1=\frac{\mathrm{v}-5}{2} \\ \mathrm{v}-5=-2 \\ \mathrm{v}=3 \mathrm{m} / \mathrm{s} \end{array}$

Chapter 2 Motion In One Dimension | Exercise 2A

Chapters in Selina Solutions CONCISE subject class 9-ICSE-Physics

Exercises in Chapter 2 Motion In One Dimension

Question 46