Selina Solutions Class 9 Physics Solutions for Exercise 2A in Chapter 2 - Chapter 2 Motion In One Dimension

Question 41 Exercise 2A

A body is moving vertically upwards. Its velocity changes at a constant rate from 50 m/s to 20 m/s in 3s. What is its acceleration?


Given: u=50m/s; v=20m/s, t=3s

\text { Acceleration }=\frac{v-u}{t}=\frac{-30}{3}=-10 \mathrm{m} / \mathrm{s}^{2}

The negative sign indicates velocity decreases with time, hence retardation is 10m/s^2.

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