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Chapter 2 Motion In One Dimension | Exercise 2A

Question 41

A body is moving vertically upwards. Its velocity changes at a constant rate from 50 m/s to 20 m/s in 3s. What is its acceleration?

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Given: u=50m/s; v=20m/s, t=3s

\text { Acceleration }=\frac{v-u}{t}=\frac{-30}{3}=-10 \mathrm{m} / \mathrm{s}^{2}

The negative sign indicates velocity decreases with time, hence retardation is 10m/s^2.

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subject-cta

Question 41

A body is moving vertically upwards. Its velocity changes at a constant rate from 50 m/s to 20 m/s in 3s. What is its acceleration?

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Given: u=50m/s; v=20m/s, t=3s

\text { Acceleration }=\frac{v-u}{t}=\frac{-30}{3}=-10 \mathrm{m} / \mathrm{s}^{2}

The negative sign indicates velocity decreases with time, hence retardation is 10m/s^2.

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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