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Chapter 1 – Measurements and Experimentation | Exercise 1B

Question 26

A screw gauge has 50 divisions on its circular scale and its screw moves by 1mm on turning it by two rotations. When the flat end of the screw is in contact with the stud, the zero of circular scale lies below the base line and 4th division of circular scale is in line with the base line. Find: (i) the pitch, (ii) the least count and (iii) the zero error, of the screw gauge.

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Given : 50 divisions on circular scale

(i) One complete rotation, or the distance travelled by the screw is the pitch

1mm movement has 2 rotations.

∴ pitch = distance / rotation = ½ = 0.5mm

(ii) Least count = Pitch/total number of divisions on circular head = 0.5/50 = 0.01mm

(iii) Zero error = coinciding division x least count

= +4 x 0.01mm = + 0.04mm

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subject-cta

Question 26

A screw gauge has 50 divisions on its circular scale and its screw moves by 1mm on turning it by two rotations. When the flat end of the screw is in contact with the stud, the zero of circular scale lies below the base line and 4th division of circular scale is in line with the base line. Find: (i) the pitch, (ii) the least count and (iii) the zero error, of the screw gauge.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Given : 50 divisions on circular scale

(i) One complete rotation, or the distance travelled by the screw is the pitch

1mm movement has 2 rotations.

∴ pitch = distance / rotation = ½ = 0.5mm

(ii) Least count = Pitch/total number of divisions on circular head = 0.5/50 = 0.01mm

(iii) Zero error = coinciding division x least count

= +4 x 0.01mm = + 0.04mm

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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