# Selina Solutions Class 9 Chemistry Solutions for Exercise 1B in Chapter 1 - Chapter 1 The Language Of Chemistry

Question 4 Exercise 1B

A microscope is provided with a main scale graduated with 20 divisions in 1cm and a vernier scale with 50 divisions on it of length same as of 49 divisions of main scale. Find the least count of the microscope.

Given: 1 main scale division = 1/20cm

50 divisions of vernier scale = 49 divisions of main scale

1 division of vernier scale = 49 ÷ 50 main scale divisions

= 0.98 main scale division

Vernier calipers:

L.C = 1 main scale division – 1 vernier scale division

= 1 main scale division – 0.98 main scale division

= 0.02 main scale division

Microscope:

1 main scale division = 1/20cm

L.C = 0.02 x 1/20 = 0.001cm

∴ Least count of the microscope is 0.001cm

Related Questions
Exercises

Lido

Courses

Teachers

Book a Demo with us

Syllabus

Maths
CBSE
Maths
ICSE
Science
CBSE

Science
ICSE
English
CBSE
English
ICSE
Coding

Terms & Policies

Selina Question Bank

Maths
Physics
Biology

Allied Question Bank

Chemistry
Connect with us on social media!