Selina solutions

# Question 13

Q13) Figure shows a brick of weight 2kgf and dimensions 20 cm \times 10 cm \times 5 cm placed in three different positions on the ground. Find the pressure exerted by the brick in each case.

Solution:

Weight of bricks = F = 2kgf

(a)

Area of base = 20 cm \times 10 cm = 200 cm^2

Pressure = Force/Area

P = 2 kgf 200 cm^2 = 0.01 kgf cm^{-2}

(b)

Area of base = Area of top = 5 cm \times 10 cm = 50 cm^2

Pressure = Force/Area

P = 2 kgf 50 cm^2 = 0.04 kgf cm^{-2}

(c)

Area of base = Area of top = 5 cm \times 20 cm = 100 cm^2

Pressure = Force/Area

P = 2 kgf 100 cm^2 = 0.02 kgf cm^{-2}

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