Selina solutions

Selina solutions

Grade 8

Physical Quantities and Measurement | Numericals

Question 2

Q2) The dimensions of a hail are 10m\times7m\times5m. If the density of air is 1.11 kg\ m^{-3}, find the mass of air in the hail.

  • Solution

  • Transcript

Solution:

Dimensions of the hall = 10m\times7m\times5m = 350\ m^{-3}

Density of air = 1.11 kg\ m^{-3}

Density\ =\ \frac{M}{V}

M=V\times D

350\ m^{-3}\ \times1.11\ kg\ m^{-3}=388.5\ kg

"hello students. Welcome to leader learning. So today our question is by Machines of the hell are 10 meters into seven meters into 5 meters. So if the density of Ares 1 Point 1 1 kg meter per Cube find the mass of air in the head. So here Haley's 10-7 into Phi. So here it is considered as volume. So D is equal to 1 Point 1 1 kg per meter cube senility is marked the volume. So try to find the mass. So here one. We know the density. We know the volume so It in the formula, so we know this is customizable volume. We don't know the mass so later Jim as M. So 1 Point 1 is equal to M by 10 into 7 into 5. So here we get tomorrow these three 88.5 kids. Thank you for watching our video. And if you have doubts, please let me know in the comment section. "

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Question 2

Q2) The dimensions of a hail are 10m\times7m\times5m. If the density of air is 1.11 kg\ m^{-3}, find the mass of air in the hail.

  • Solution

  • Transcript

Solution:

Dimensions of the hall = 10m\times7m\times5m = 350\ m^{-3}

Density of air = 1.11 kg\ m^{-3}

Density\ =\ \frac{M}{V}

M=V\times D

350\ m^{-3}\ \times1.11\ kg\ m^{-3}=388.5\ kg

"hello students. Welcome to leader learning. So today our question is by Machines of the hell are 10 meters into seven meters into 5 meters. So if the density of Ares 1 Point 1 1 kg meter per Cube find the mass of air in the head. So here Haley's 10-7 into Phi. So here it is considered as volume. So D is equal to 1 Point 1 1 kg per meter cube senility is marked the volume. So try to find the mass. So here one. We know the density. We know the volume so It in the formula, so we know this is customizable volume. We don't know the mass so later Jim as M. So 1 Point 1 is equal to M by 10 into 7 into 5. So here we get tomorrow these three 88.5 kids. Thank you for watching our video. And if you have doubts, please let me know in the comment section. "

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your physics exam ?

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subject-cta
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