Selina solutions

Selina solutions

Grade 8

Physical Quantities and Measurement | Numericals

Question 11

Q11) The mass of an empty density bottle is 30 g, it is 75 g when filled completely with water and 65 g when filled completely with a liquid. Find:

(a) volume of density bottle

(b) density of liquid: and

(c) relative density of liquid.

Solution:

Mass of empty density bottle, M1 = 30g

Mass of bottle + Water, M2 = 75g

Mass of liquid + bottle, M3 = 65g

Mass of water = M2-M1 = 75 - 30 = 45g

(a) Volume of density bottle = Mass of water = 45g

(b) Density of liquid x = ? \frac{Mass\ of\ liquid}{Mass\ of\ water}=\frac{35}{45}=0.77\ g\ cm^{-3}

Mass of liquid = M3 - M1 = 65 - 30 = 35g

(c) Mass of water in the density bottle = 75 - 30 = 45g

Mass of equal volume of liquid in density bottle 65-30 = 35g

Relative Density of liquid = \frac{mass\ of\ 45\ cc\ ofliquid}{mass\ of\ 45\ cc\ of\ water}=\frac{35}{45}=\frac{7}{9}=0.77\

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subject-cta

Question 11

Q11) The mass of an empty density bottle is 30 g, it is 75 g when filled completely with water and 65 g when filled completely with a liquid. Find:

(a) volume of density bottle

(b) density of liquid: and

(c) relative density of liquid.

Solution:

Mass of empty density bottle, M1 = 30g

Mass of bottle + Water, M2 = 75g

Mass of liquid + bottle, M3 = 65g

Mass of water = M2-M1 = 75 - 30 = 45g

(a) Volume of density bottle = Mass of water = 45g

(b) Density of liquid x = ? \frac{Mass\ of\ liquid}{Mass\ of\ water}=\frac{35}{45}=0.77\ g\ cm^{-3}

Mass of liquid = M3 - M1 = 65 - 30 = 35g

(c) Mass of water in the density bottle = 75 - 30 = 45g

Mass of equal volume of liquid in density bottle 65-30 = 35g

Relative Density of liquid = \frac{mass\ of\ 45\ cc\ ofliquid}{mass\ of\ 45\ cc\ of\ water}=\frac{35}{45}=\frac{7}{9}=0.77\

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subject-cta
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