Selina solutions

Selina solutions

Grade 7

Light energy | Short/Long Answer Questions

Question 12

Q12) The following diagram shows an incident ray AO and the normal ON on a plane mirror. Find the angle of incidence and angle of reflection.

Solution :

ON is a perpendicular on a plane mirror

Angle of incidence ∠i which is ∠AON

Angle between incident ray and normal ray = 90° - 30°

Angle of reflection = 60°

∠i = ∠r

Angle between incident and reflected ray which is ∠AOB

60 + 60 = 120°

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subject-cta

Question 12

Q12) The following diagram shows an incident ray AO and the normal ON on a plane mirror. Find the angle of incidence and angle of reflection.

Solution :

ON is a perpendicular on a plane mirror

Angle of incidence ∠i which is ∠AON

Angle between incident ray and normal ray = 90° - 30°

Angle of reflection = 60°

∠i = ∠r

Angle between incident and reflected ray which is ∠AOB

60 + 60 = 120°

Still have questions? Our expert teachers can help you out

Book a free class now

Want to top your physics exam ?

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subject-cta
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