A body of 2 kg falls from rest. What will be its kinetic energy during the fall at the end of 2s?

Answer:

Mass of body = 2 kg

Initial velocity, u = 0

Time taken, t = 2 s

Acceleration due to gravity, g = 10 m/s2

Final velocity, v = ?

Using the first equation of motion,

v = u + gt = 20 m/s

KE = \frac{1}{2}mv^2 = 400 J [

"hey kids welcome to lido q a video
i am vinit your leader tutor bringing
you this question on your screen
a body of 2 kg falls from rest what will
be its kinetic energy
during the fall at the end of two
seconds
here the time is given to you the mass
is given to you
initial velocity is zero
for kinetic energy we need the final
velocity
but we don't have it so let us find it
so what is given to you u is equal to
0 meter per second mass is
2 kg time is equal to 2 second
and g we know is 9.8 meter per second
square now
we know
u sorry v is equal to u plus
gt this implies v
is equal to u 0 plus 9.8 into 2
this implies v is equal to 19.6
meter per second right
now
let us find the kinetic energy of the
body now that we have
v so kinetic energy is
equal to half mv square
that is equal to half into mass is 2 kg
into 19.6 whole square
so this is equal to
19.6 square is 384
0.16 in june isn't that easy guys
if you still have it out though please
leave a comment below
do like the channel and subscribe to our
video do like the video and subscribe to
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