A ball of mass 200g falls from a height of 5 meters. What is its kinetic energy when it just reaches the ground?
Mass = 200 g = 0.2kg
Height = 5m
Initial velocity, u = 0
Acceleration due to gravity, g = 9.8 m/s2
Final velocity, v
Using the third equation of motion,
v^2-u^{2\ }=2gs^{ }
v^2 = 98
Kinetic energy = \frac{1}{2}mv^2
Kinetic energy = (½)(0.2)(98) = 9.8J
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies