Lakhmir Singh Solutions Class 9 Physics Solutions for Exercise in Chapter 3 - Gravitation
Prev
a) Is the acceleration due to the gravity of earth ‘g’ a constant? Discuss.
b) Calculate the acceleration due to gravity on the surface of a satellite having a mass of 7.4\ \times10^{22\ } kg and a radius of 1.74\times10^6 m. Which satellite do you think it could be?
a) No, the value of acceleration due to gravity is no constant at all the places on the surface of the earth. This is because the radius of the earth is minimum at the poles while the maximum at the equator. The value of g is maximum at the poles and minimum at the equator. The value of g increases as we go from the centre of the earth towards the poles and the value of g decreases as we go inside the earth. b) Acceleration due to gravity,
g = G M/R2
Mass, M = 7.4\ \times10^{22\ } kg
Radius, R = 1.74\times10^6 m
Gravitational constant, G = 6.7\times10^{-11}\ Nm^2/kg^2
Therefore, substituting the values we get g = 1.637 m/s^2
Facebook
Whatsapp
Copy Link
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies
