a) Is the acceleration due to the gravity of earth āgā a constant? Discuss.

b) Calculate the acceleration due to gravity on the surface of a satellite having a mass of 7.4\ \times10^{22\ } kg and a radius of 1.74\times10^6 m. Which satellite do you think it could be?

Answer:

a) No, the value of acceleration due to gravity is no constant at all the places on the surface of the earth. This is because the radius of the earth is minimum at the poles while the maximum at the equator. The value of g is maximum at the poles and minimum at the equator. The value of g increases as we go from the centre of the earth towards the poles and the value of g decreases as we go inside the earth. b) Acceleration due to gravity,

g = G M/R2

Mass, M = 7.4\ \times10^{22\ } kg

Radius, R = 1.74\times10^6 m

Gravitational constant, G = 6.7\times10^{-11}\ Nm^2/kg^2

Therefore, substituting the values we get g = 1.637 m/s^2

"hey kids welcome to lido q a video
i am vineet your lido tutor bringing you
this question on your screen
now question is
is the acceleration due to gravity of
earth g
a constant discuss so let us
answer the first question discuss the
first question
and then answer the second question so
the clear answer for this is
no
the acceleration due to gravity of earth
earth is not
is not constant
constant
at all the places on the surface of the
earth
all the places
on the surface
of the earth
why is this this is because the radius
of the earth is minimum
this is because
the radius
of the earth is minimum
at the poles and
poles so i'll have to continue this here
and maximum near the
equator right now
how does that impact
the uh
acceleration due to gravity this impacts
the acceleration due to gravity
because
this actually impacts the acceleration
due to gravity
because the value of g if
is inversely proportional to the radius
or the distance
right so that that's how so
the value of
g is maximum
at the poles and approaches
zero as we
move to the center
or the core of the earth
right now this is
party let us look
let us all part b now
now in part b it is given to us that
mass of earth is mass of the satellite
is
7.4 into
10 to the power 22 kg
and radius of the satellite
is 1.74
into 10 to the power
6 meter right
and g we know is equal to 6.6
7 into 10 to the power minus 11
newton meter square per
second square
now g is given by
we know that g is equal to
gravitational constant into mass
by radius square
so substituting the values and solving
we get g is equal to 1.637
meter per second square isn't that easy
guys
if you still have a doubt though please
leave a comment below
do like the video and subscribe to our
channel and see you in our next video
until then bye guys keep learning"

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