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Rd sharma solutions

CHAPTERS

6. Algebraic Expressions and Identities

8. Division of Algebraic Expressions

9. Linear Equation in One Variable

10. Direct and Inverse Variations

13. Profit Loss Discount and Value Added Tax

15. Understanding Shapes Polygons

16. Understanding Shapes Quadrilaterals

17. Understanding Shapes Special Types Quadrilaterals

20. Area of Trapezium and Polygon

21. Volume Surface Area Cuboid Cube

22. Surface Area and Volume of Right Circular Cylinder

23. Classification And Tabulation Of Data

24. Classification And Tabulation Of Data Graphical Representation Of Data As Histograms

25. Pictorial Representation Of Data As Pie Charts Or Circle Graphs

A and B can finish a work in 20 days. A alone can do 1/5th of the work in 12days. In how many days can B alone do it?

The given details are,

A and B can finish a work in = 20 days

(A+ B)’s 1 day work = 1/20

A can finish 1/5th of work in = 12 days

A’s 1 day work = 1/(5×12) = 1/60

We know that,

B’s 1 day work = (A+B)’s 1 day work – A’s 1 day work

= 1/20 – 1/60

= (3-1)/60

= 2/60

= 1/30

∴ B alone can finish the work in = 1/(1/30) = 30days.

Algebraic Expressions and Identities

Division of Algebraic Expressions

Linear Equation in One Variable

Profit Loss Discount and Value Added Tax

Understanding Shapes Quadrilaterals

Understanding Shapes Special Types Quadrilaterals

Volume Surface Area Cuboid Cube

Surface Area and Volume of Right Circular Cylinder

Classification And Tabulation Of Data

Classification And Tabulation Of Data Graphical Representation Of Data As Histograms

Pictorial Representation Of Data As Pie Charts Or Circle Graphs

The given details are,

A and B can finish a work in = 20 days

(A+ B)’s 1 day work = 1/20

A can finish 1/5th of work in = 12 days

A’s 1 day work = 1/(5×12) = 1/60

We know that,

B’s 1 day work = (A+B)’s 1 day work – A’s 1 day work

= 1/20 – 1/60

= (3-1)/60

= 2/60

= 1/30

∴ B alone can finish the work in = 1/(1/30) = 30days.

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