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A piece of stone is thrown vertically upwards. It reaches the maximum height in 3 seconds. If the acceleration of the stone be 9.8 m/s^2 directed towards the ground, calculate the initial velocity of the same with which it is thrown upwards.

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The initial velocity of the stone, u = ?

Final velocity of stone, v = 0

Acceleration due to gravity, g = m/s^2

Time, t = 3s

Using the relation, v = u + gt

We get, u = 29.4 m/s

"hey kids welcome to lido q a video i am vinit your leader tutor bringing you this question on your screen a piece of stone is thrown vertically upwards it reaches the maximum height in three seconds if the acceleration of the stone be 9.8 meter per second square that is the acceleration due to gravity directed towards the ground calculate the initial velocity of the same with which it is thrown upwards now the final velocity is equal to zero meter per second because it comes to a halt at the end acceleration due to gravity is equal to 9.8 meter per second square and time is equal to 3 seconds right now we know v is equal to u plus a t since acceleration is acceleration due to gravity here we'll write it as v equal to u plus gt that means zero is equal to u plus nine point eight into three three right therefore u is equal to minus 9.8 into 3 that is equal to minus 29.4 meter per second therefore initial velocity the negative sign implies that the velocity is in the downward direction in downward direction isn't that easy guys if you still have a doubt please leave a comment below do like the video and subscribe to our channel i'll see you in our next video until then bye kids keep practicing keep learning "

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