Lakhmir Singh Solutions Class 9 Physics Solutions for Exercise in Chapter 2 - Force and Laws of Motion
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a) Explain why a cricket player moves his hands backward while catching a fast cricket ball.
b) A 150g ball, traveling at 30 m/s strikes the palm of a player’s hand and is stopped in 0.05 seconds. Find the force exerted by the ball on the hand.
Answer:
a) A cricket player moves his hands backward while catching a fast cricket ball so that the momentum of the ball reduces to zero as the momentum of the fast-moving ball is large. By moving his hand, he is increasing the time taken thereby reducing the momentum.
b) Mass of ball = 150g = 0.15 kg
Initial velocity, u = 30 m/s
Final velocity, v = 0 m/s
Time, t = 0.05s
Acceleration, a = (v-u)/t = 6000 \mathrm{m/ s^2}
Force = ma = 90N
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