Lakhmir Singh Solutions Class 9 Physics Solutions for Exercise in Chapter 2 - Force and Laws of Motion
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A body of mass 5kg is moving with a velocity of 10 m/s. A force is applied to it so that in 25 seconds, it attains a velocity of 35 m/s. Calculate the value of the force applied.
Answer:
Mass of the body = 5kg
Initial velocity, u = 10 m/s
Final velocity, v = 35 m/s
Time, t = 25s
Acceleration, a = (v-u)/t = 1 \mathrm{m} / \mathrm{s}^{2}
Force = ma = 5N
Video transcript
"hey guys predo q a video i am vineeth
your lido tutor
bringing you this question on your
screen
a body of mass 5 kg is moving
with a velocity of 10 meter per second
a force is applied to it so that
in 25 seconds it attains a velocity of
35 meter per second calculate the value
of the
force applied so here we have
the mass 5 kg initial velocity
10 meter per second the time is 25
seconds
and the final velocity is 35 meter per
second
so m is equal to 5 kg
u is 10 meter per second
t is equal to 25 seconds and
final velocity is 35 meter per second
we know
v is equal to u plus e t
this implies a is equal to v minus u by
t so this will be equal to
35 minus 10 by
25 equal to 1 meter per second square
right now we have the mass and the
acceleration
so we can find the force therefore
force applied
is equal to mass into acceleration that
is 5 into 1
equal to 5 newton isn't that easy guys
right if you still have a doubt please
leave a comment below
do like the video and subscribe to our
channel and see you in our next video
until then bye guys keep learning"
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