# Lakhmir Singh Solutions Class 9 Physics Solutions for Exercise in Chapter 2 - Force and Laws of Motion

Question 77 Exercise

A body of mass 5kg is moving with a velocity of 10 m/s. A force is applied to it so that in 25 seconds, it attains a velocity of 35 m/s. Calculate the value of the force applied.

Answer:

Mass of the body = 5kg

Initial velocity, u = 10 m/s

Final velocity, v = 35 m/s

Time, t = 25s

Acceleration, a = (v-u)/t = 1 \mathrm{m} / \mathrm{s}^{2}

Force = ma = 5N

Video transcript
"hey guys predo q a video i am vineeth your lido tutor bringing you this question on your screen a body of mass 5 kg is moving with a velocity of 10 meter per second a force is applied to it so that in 25 seconds it attains a velocity of 35 meter per second calculate the value of the force applied so here we have the mass 5 kg initial velocity 10 meter per second the time is 25 seconds and the final velocity is 35 meter per second so m is equal to 5 kg u is 10 meter per second t is equal to 25 seconds and final velocity is 35 meter per second we know v is equal to u plus e t this implies a is equal to v minus u by t so this will be equal to 35 minus 10 by 25 equal to 1 meter per second square right now we have the mass and the acceleration so we can find the force therefore force applied is equal to mass into acceleration that is 5 into 1 equal to 5 newton isn't that easy guys right if you still have a doubt please leave a comment below do like the video and subscribe to our channel and see you in our next video until then bye guys keep learning"
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