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NCERT Solutions Class 10 Mathematics Solutions for Areas Related to Circles - Exercise 12.2 in Chapter 12 - Areas Related to Circles

Question 18 Areas Related to Circles - Exercise 12.2

A chord of a circle of radius 14 cm subtends an angle of 60° at the centre. Find the area of the corresponding segment of the circle. (Use π = 22/7 and √3 = 1.73)

Answer:

Area of sector OAYB = \frac{\theta}{360°}\times\pi r^2

= \frac{60°}{360°}\times\frac{22}{7}\times14\times14

= \frac{308}{3}=102.67\ cm^2

Side of equilateral △OAB = 14 cm

Area of △OAB = \frac{\sqrt{3}}{4}\times14\times14=84.77\ cm^2

Area of minor segment AYB = 102.67\ cm^2-84.77\ cm^2=17.9\ cm^2

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