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A canal is 300 cm wide and 120 cm deep. The water in the canal is flowing with a speed of 20 km/hr. How much area will it irrigate in 20 minutes if 8 cm of standing water is desired?

Answer:

It is given that the canal is the shape of a cuboid with dimensions as:

Breadth (b) = 300 cm and Height (h) = 120 cm

It is also given that

The speed of canal = 20 km/hr

Length of canal covered in 1 hour (60 minutes) = 20 km

Length of canal covered in 20 min = 20/3 km = 20/3 × 100000 cm

We know that the canal is cuboidal in shape.

So,

Volume of canal = l x b x h

= 20/3 × 100000 × 300 × 120 cm^{3}

= 24 x 10^{9} cm^{3}

Volume of water in canal = Volume of area irrigated

Volume of area irrigated = Area irrigated x Height

24 x 10^{9} cm^{3} = Area irrigated x 8 cm

Thus, area irrigated = 3 x 10^{9} cm²

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