A dice is rolled once. What is the probability that the number on top will be a multiple of 3 ?
A dice is rolled once, the possible outcomes are 1, 2, 3, 4, 5 and 6.
Then,
The probability that the number on top will be a multiple of 3
Multiple of 3 = 3 and 6
Then,
Probability = total number of multiple of 3/ Total number of outcomes
= 2/6 … [divide numerator and denominator by 2]
= 1/3
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