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A 117\frac{1}{3} m long rope is cut into equal pieces measuring 7\frac{1}{3}m each. How many such small pieces are these? Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

From the question it is given that,

The length of the rope = 117\frac{1}{3} m

=\frac{(117\times3+1)}{3}=\frac{352}{3}\ m

Then length of each piece measures = 7\frac{1}{3} m=\frac{22}{3}m

So, the number of pieces of the rope

=\frac{total\ length\ of\ the\ rope}{length\ of\ each\ piece}=\frac{352}{3}\div\frac{22}{3}

=\frac{352}{3}\times\frac{3}{22}=\frac{16}{1}\times\frac{1}{1}

= 16

Hence, number of small pieces cut from the 117\frac{1}{3} m long rope is 16.

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