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Ncert solutions
Data Handling | Exercise 3.1
Question 13
A cricketer scores the following runs in eight innings:
58, 76, 40, 35, 46, 45, 0, 100.
What is the mean score?
Mean score = \frac{(Total\ runs\ scored\ by\ the\ cricketer\ in\ all\ innings)}{(Total\ number\ of\ innings\ played\ by\ the\ cricketer)}
Total runs scored by the cricketer in all innings = 58 + 76 + 40 + 35 + 46 + 45 + 0 + 100
= 400
Total number of innings = 8
Then,
Mean = \frac{400}{8}
= 50
∴Mean score of the cricketer is 50.
Question 13
A cricketer scores the following runs in eight innings:
58, 76, 40, 35, 46, 45, 0, 100.
What is the mean score?
Mean score = \frac{(Total\ runs\ scored\ by\ the\ cricketer\ in\ all\ innings)}{(Total\ number\ of\ innings\ played\ by\ the\ cricketer)}
Total runs scored by the cricketer in all innings = 58 + 76 + 40 + 35 + 46 + 45 + 0 + 100
= 400
Total number of innings = 8
Then,
Mean = \frac{400}{8}
= 50
∴Mean score of the cricketer is 50.
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