A floor is 4.5 m long and 3.6 m wide. A 6 cm square tile costs 23.25. What will be the cost to cover the floor with these tiles?
Length of the floor = 4.5 m
= (4.5 × 100) cm = 450 cm
Width of the floor= (3.6 × 100) cm = 360 cm
∴ Area of the floor – (450 × 360) cm2 = 162000 cm²
Side of a square tile = 6 cm
∴ Area of one square tile = (6 × 6) cm2 = 36 cm²
Number of tiles reqnuired to cover the floor=\frac{\text{ Area of floor }}{\text{ Area of one tile }}=\frac{162000}{36}=4500
Now, cost of one tile = ₹ 23.25
∴ Cost of 4500 tiles =₹ (23.25 ×4500)
= ₹ 104625
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