A hill, 101\frac{1}{3}m in height, has 1/4th of its height under water. What is the height of the hill visible above the water?
\text { Height of the hill }=101 \frac{1}{3} m=\frac{304}{3} m \\ \text { Hill's height under water }=\frac{1}{4} \times \frac{304}{3}=\frac{76}{3} m \\
Therefore, hill visible above the water
=\left(\frac{304}{3}-\frac{76}{3}\right)=\frac{228}{3}=76 m
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