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NCERT Solutions Class 10 Mathematics Solutions for Arithmetic Progressions - Exercise 5.2 in Chapter 5 - Arithmetic Progressions
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30th term of the A.P: 10, 7, 4, …, is
Answer:
Given here,
A.P. = 10, 7, 4, …
Therefore, we can find,
First term, a = 10
Common difference, d = a2 − a1 = 7−10 = −3
As we know, for an A.P.,
an = a +(n−1)d
Putting the values;
a30 = 10+(30−1)(−3)
a30 = 10+(29)(−3)
a30 = 10−87 = −77
Hence, the correct answer is option C.
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