Jump to

- Pair of Linear Equations in Two Variables - Exercise 3.1
- Pair of Linear Equations in Two Variables - Exercise 3.2
- Pair of Linear Equations in Two Variables - Exercise 3.3
- Pair of Linear Equations in Two Variables - Exercise 3.4
- Pair of Linear Equations in Two Variables - Exercise 3.5
- Pair of Linear Equations in Two Variables - Exercise 3.6
- Pair of Linear Equations in Two Variables - Exercise 3.7

**5 pencils and 7 pens together cost 50, whereas 7 pencils and 5 pens together cost 46. Find the cost of one pencil and that of one pen.**

Answer:

Let 1 pencil costs Rs.x and 1 pen costs Rs.y.

According to the question, the algebraic expression cab be represented as;

5x + 7y = 50

7x + 5y = 46

For, 5x + 7y = 50 or x = (50-7y)/5, the solutions are;

For 7x + 5y = 46 or x = (46-5y)/7, the solutions are;

Hence, the graphical representation is as follows;

From the graph, it is can be seen that the given lines intersect each other at point (3, 5).

So, the cost of a pencil is 3/- and cost of a pen is 5/-.

Related Questions

Exercises

Chapters

Lido

Courses

Quick Links

Terms & Policies

Terms & Policies

2022 © Quality Tutorials Pvt Ltd All rights reserved