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NCERT Solutions Class 10 Mathematics Solutions for Probability - Exercise 15.1 in Chapter 15 - Probability
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A die is thrown once. Find the probability of getting an odd number.
Answer:
Total possible events when a dice is thrown = 6 (1, 2, 3, 4, 5, and 6)
P(E) = (Number of favourable outcomes/ Total number of outcomes)
Total number of odd numbers = 3 (1, 3 and 5)
P (getting an odd number) = 3/6 = ½ = 0.5
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